Q.

The solubility in water of a sparingly soluble salt AB2 is 1.0 x 10-5 mol L-1. Its solubility product Will

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a

1 X 1O-1O

b

4 X 1O-1O

c

4 X 10-15

d

1 X 10-15

answer is A.

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Detailed Solution

AB21A 2+S+2B2S

By the relation of solubility product and solubility,

Ksp=A2+B2Ksp=S(2S)2

After putting S=10−5 M,

Ksp=105×2×1052Ksp=4×1015

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