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The solubility of Sr(OH)₂ at 298 K is 12.162 g/L of solution.[OH^-] concentration of solution is
[Mol.wt of Sr(OH)₂ = 121.62]

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0.02

0.1

0.05

0.2

answer is B.

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Detailed Solution

Molarity = solubility for sparingly soluble salt

S = $\frac{12.162}{121.62} = 0.1$ M

$Sr {(OH)}_{2} ⇌ {Sr}^{+ 2} + 2 {OH}^{-}$

[OH^-] = 2 $\times$ 0.1=0.2M

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