The solubility of $CdS{O}_4$ Its solubility in 0.01M $H_{2}S{O}_4$

$$\begin{gathered} CdS{O}_4 \left(s\right) \rightleftharpoons \underset{S}{C{d}^{2+ }} + \underset{S}{S{O_4}^{2-}} \\ S = 8 \times {10}^{-4} \\ {K}_{sp} = S^2 = 64 \times {10}^{-8} \\ In H_{2}S{O}_4 \end{gathered}$$

$$\begin{gathered} CdS{O}_4 ( s ) \rightleftharpoons C{d}^{2+} + S{O_4}^{2-} \\ Ksp( CdS{O}_4) = S( S + {10}^{-2} ) \\ Ksp( CdS{O}_4 ) = S \times {10}^{-2} \\ 64 \times {10}^{-8}= S \times {10}^{-2} \\ S = 64 \times {10}^{-6} \end{gathered}$$

Hence, the correct answer is 64.