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Q.

The solubility product of a salt having general formula ${MX}_{2}$ , in water is $4 \times 10^{- 12}$ The concentration of $M^{2 +}$ ions in the saturated aqueous solution of the salt is:

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a

$1.6 \times 10^{- 4} M$

b

$2.0 \times 10^{- 6} M$

c

$1.0 \times 10^{- 4} M$

d

$4.0 \times 10^{- 10} M$

answer is B.

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Detailed Solution

The solubility product,

$4 s^{3} = 4 \times 10^{- 12} \Rightarrow s = 10^{- 4} = [M^{2 +}]$

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The solubility product of a salt having general formula MX2 , in water is 4×10−12 The concentration of M2+ ions in the saturated aqueous solution of the salt is: