Q.

The solubility product of a sparingly soluble salt A2X3 is 1.1×1023. If specific conductance of the solution is 3×105Sm1, the limiting molar conductivity of the solution is x×103Sm2mol1. The value of x is ________.

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answer is 3.

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Detailed Solution

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A2X3(s)2A(aq)+3+3X(qq)2
solubility sM 2s 3s
(2s)2(3s)3=1.1×1023108s5=1.1×1023s105M=105molL=0.01molm3 Now mm=km=ksm=3×1050.01=3×103Sm2/mol

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