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Q.

The Solubility product of AgCl is 10-10. what volume of water (in liters) is required to dissolve 2.87 mg. of AgCl  

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a

1 Lit

b

2 Lit

c

4 Lit

d

10 Lit

answer is B.

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Detailed Solution

Ksp of AgCl=10−10=S2;S=10−5 mole / lit 
But   M=wtM.wtx1V.inLit
10−5=2.87×10−3143.5X1 V.inlit ;V=2 Lit 

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The Solubility product of AgCl is 10-10. what volume of water (in liters) is required to dissolve 2.87 mg. of AgCl