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The solubility product of CuS, Ag₂S and HgS are 10^–31, 10^–44 and 10^–54 respectively. The solubilities of these sulphides are in the order of

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Ag₂S > CuS > HgS

Ag₂S > HgS > CuS

HgS > Ag₂S > CuS

CuS > Ag₂S > HgS

answer is A.

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Detailed Solution

The solubility product (Ksp) and solubility (S) are inversely related: a lower Ksp indicates less solubility, and a higher Ksp indicates more solubility. Given the Ksp values for the sulfides:

CuS: 10−3110−31
Ag₂S: 10−4410−44
HgS: 10−5410−54

The solubility is in the inverse order of Ksp values:

Solubility: CuS>Ag2S>HgS

Thus, among CuS, Ag₂S, and HgS, CuS is the most soluble, and HgS is the least soluble.

Order of solubilities:

CuS>Ag₂S>HgS

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