The solubility product of Hg₂I₂ is equal to

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[Hg⁺²][I^-]

[Hg₂⁺²][I^-]

[Hg₂⁺²][I^-]²

[Hg⁺²]² [I^-]²

answer is C.

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Detailed Solution

Dissociation of Hg₂I₂ in Water

Mercury(I) iodide (Hg₂I₂) dissociates in water as follows:

Hg₂I₂ (s) ⇌ Hg₂²⁺ (aq) + 2I⁻ (aq)

Solubility Product Expression

The solubility product (K_sp) is derived from the concentrations of the ions at equilibrium, each raised to the power of their stoichiometric coefficients:

Ksp = [Hg₂²⁺] × [I⁻]²

Correct Option:

c) [Hg₂²⁺][I⁻]²

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