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Q.

The solubility product of sparingly soluble salt A2X3 is 1.1x1023 If specific conductance of the solution is 3x105Sm1, the limiting molar conductivity of the solution is x x 103Sm2mole1 The value of  x is __________

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answer is 3.

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Detailed Solution

KSP=108S5S=(1.1 x 1023108)151 x 105s=105moleL=102moleM3λm=ks=3 x 105102=3x103=3

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