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Q.

The solubility product of the electrolyte of the type, $A_{2} B_{3} is$ (s is the solubility in mol/lit)

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a

$108 s^{5}$

b

$72 s^{5}$

c

$108 s^{2}$

d

$10 s^{2}$

answer is A.

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Detailed Solution

$A_{3} B_{3} ⇌ 2 A^{+ 2} + 3 B^{- 2}$

2s 3s

$K_{sp} = {(2 s)}^{2} {(2 s)}^{3} = 4 s^{2} \times 273^{3} = 108 s^{5}$

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