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The solution containing 6.8g of non-ionic solute in 100g of water was found to freeze at – 0.93°C. If K_f for water is 1.86, the molar Mass of solute is

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136

13.6

answer is D.

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Detailed Solution

M = $\frac{K_{f} \times W_{B} \times 1000}{∆ T_{f} \times W_{A}}$

M = $\frac{1.68 \times 6.8 \times 1000}{0.93 \times 100}$

M =136

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