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Q.

The solution of a[xdy + ydx] = xy dy

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a

x + y = xy + c

b

a log(xy) = y + c

c

x + c = a log(xy)

d

xy = y + c

answer is A.

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Detailed Solution

Givena[xdy+ydx]=xydyaD(xy)xy=dyaD(xy)xy=dyalog(xy)=y+c

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