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Q.

The solution of the differential equation cos2xd2ydx2=1 is:

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a

y = log cos x + ex 

b

None of these 

c

y=logsecx+c1x+c2 and y=logsecxc1x+c2

d

y=logsecxc1x+c2+c3

answer is B.

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Detailed Solution

     cos2xd2ydx2=1

 d2ydx2=sec2x

On integrating, we get dydx=tanx±c1

Again integrating, we get y=logsecx±c1x±c2.

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