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Q.

The solution of the differential equation dydx-2y tan2x=exsec2x is : 

 

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a

ycos2x=ex+ c

b

y=ex cos2x+ c

c

ysin2x=ex+ c

d

ycos2x+ex=c

answer is B.

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Detailed Solution

I.F=e-2tan 2x dx =e-log sec2x =1sec2x

Multiplying the D.E with I.F

cos2xdydx-2y sin 2x=excos2x dy-2y sin2x dx=exdxdy cos2x=ex dxy cos2x=ex dxy cos2x=ex+c

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