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Q.

The solution of the differential equation

x2yx2dydx+y2+xy2=0, is

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a

logxy=1x+1y+C

b

logyx=1x+1y+C

c

log(xy)=1x+1y+C

d

log(xy)+1x+1y=C

answer is A.

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Detailed Solution

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The given differential equation is

x2(1y)dydx+y2(1+x)=0x2(1y)dy+y2(1+x)dx=01yy2dy+1+xx2dx=0

On integrating, we get 

1ylogy1x+logx=C or, logxy=1x+1y+C

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