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Q.

The solution of (81)sin2x+(81)cos2x=30 in  [0,π2] is

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a

π3,π2

b

π6,π3

c

π4,π2

d

π,π2

answer is A.

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Detailed Solution

81sin2x+81cos2x=30[0,π2]

81sin2x+811sin2x=30

81sin2x+8181sin2x=30

81sin2x=a

a+81a=30

a2+8130a=0

a230a+81=0

a227a3a+81=0

a(a27)3(a27)=0

(a27)(a3)=0

a=27,a=3

81sin2x=33

34sin2x=33

4sin2x=33

4sin2x=3

sin2x=34

x=60

34sin2x=31

sin2x=14

x=30°

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