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Q.

The solution of dydx+y cosx+siny+ysinx+x cosy+x=0 is

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a

sin x + sin y + xy = k

b

xy (sin x + sin y + 1) = k

c

y sin x + x sin y + xy = k

d

y cos x + x cos y + xy = k

answer is B.

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Detailed Solution

dydx=ycosxsinyysinx+xcosy+xsinxdy+xcosydy+xdy=ycosxdxsinydxydxsinxdy+sinydx+xcosydy+ycosxdx+xdy+ydx=0(sinxdy+ycosxdx)+(sinydx+xcosydy)+(xdy+ydx)=0D(ysinx)+D(xsiny)+D(xy)=0ysinx+xsiny+xy=k

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