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Q.

 The solution set of the equation cos5x=1+sin4x is 

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a

nπ,nI

b

2nπ,nI

c

4nπ,nI

d

nπ2,nI

answer is B.

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Detailed Solution

cos5x=1+sin4x

Minimum value of RHS is 1 and maximum value of LHS is 1. So equality holds only when both sides are simultaneously 1

 i.e. cosx=1 and sinx=0

x=2nπ and x=nπ

 So, solution set, x=2nπ

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