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Q.

The solution set of log1/2x21>0 is 

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a

(2,1)(1,2)

b

(1,2)

c

(2,1)

d

(2,2)

answer is D.

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Detailed Solution

 base =12<1x21<1x22<0x(2,2) but x21>0x(,1)(1,)⇒∴ sol =(2,1)(1,2)

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