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Q.

The solutions of the equation

1+sin2xsin2xsin2xcos2x1+cos2xcos2x4 sin 2x4 sin 2x1+4 sin 2x=0, (0<x<π) are

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a

π12, π6

b

7π12, 11π12

c

5π12,7π12

d

π6, 5π6

answer is B.

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Detailed Solution

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    R1R1+R2+R3  (2+4sin2x) 1   1   1cos2x1+cos2xcos2x4sin2x4sin2x1+4sin2x=0 sin2x=-12      2x=π+π6,  2π-π6        x=π2+π12,  π-π12          =7π12,  11π12

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