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Q.

The space has electromagnetic field which varies with time whose variation is given as
B=B0k^ if 0tπmqB0B0j^ if πmqB0<t2πmqB00 if 2πmqB0<t<          
and  E={0 if 0t2πmqB0E0k^ if 2πmqB0<t<
A charge particle having mass m and positive charge q is given velocity  v0i^ at origin at t=0  sec. The coordinate of point on xy plane when it is passing through xy plane again is
 

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a

(2mv0qv0E0 B0,2mv0qB0,0)

b

(2mv0qv0E0 B0,mv0qB0,0)

c

(mv0qv0E0 B0,mv0qB0,0)

d

(mv0qv0E0 B0,2mv0qB0,0)

answer is A.

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Detailed Solution

f(x)=a2x3+ax2x+b   f'(x)=3a2x2+2ax1

Local minimum  x=1   2mv0qB0=12(qE0 m)t2   4 m2v0q2E0 B0=t2, x=v0×2 mqv0E0 B0

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