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Q.

The species having smallest ionic radius is :

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a

Al3+

b

K+

c

Ba2+

d

Mg2+

answer is A.

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Detailed Solution

Ionic radius of Al3+ is equal to 53.
Ionic radius of Ba2+ is equal to 135.
Ionic radius of K+ is equal to 138.
Ionic radius of Mg2+ is equal to 72.

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