The species that has a spin only magnetic moment of 5.9 BM, is ( $T_{d} =$ tetrahedral)

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$N i {(C O)}_{4} (T_{d})$

${[N i C l_{4}]}^{2} - (T_{d})$

${[N i {(C N)}_{4}]}^{2 -}$ -(square planar)

${[M n B r_{4}]}^{2} - (T_{d})$

answer is D.

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Detailed Solution

$= 5.9 B M$

Number of unpaired electrons = 5
${[M n B r_{4}]}^{2 -} M n_{2}^{+} = [A r] 3 d^{5} 4 s^{0}$
Question Image
$B r^{Θ}$ is a weak field ligand.
$n = 5 μ = \sqrt{5 (5 + 2)} B M = 5.9 B M$

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