Q.

The specific conductance of 0.0025 M acetic acid is 5×105Scm1 at a certain temperature. The dissociation constant of acetic acid is ___________×107.  (nearest integer)
Consider limiting molar conductivity of CH3COOH as 400Scm2mol1 

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answer is 66.

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Detailed Solution

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K=5×105scm1M=0.0025Mm=k×1000mm=5×105×1030.0025m=400=mcm=20400=0.05Ka=ca21α=66

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The specific conductance of 0.0025 M acetic acid is 5×10−5S cm−1 at a certain temperature. The dissociation constant of acetic acid is ___________×10−7.  (nearest integer)Consider limiting molar conductivity of CH3COOH as 400 S cm2mol−1