The specific conductance of 0.1N KCl solution $at 23^{0} C is 0 .0112 {ohm}^{- 1} {cm}^{- 1} .$ The resistance of cell containing the solution at the same temperature was found to be 55 ohm. The cell constant will be

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0.142cm^–1

0.616cm^–1

0.918cm^–1

1.12 cm^–1

answer is B.

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Detailed Solution

$s p e c i f i c c o n d u c t i v i y t (k) = \frac{1}{R} \times c e l l c o n s \tan t \frac{1}{R} = \frac{1}{55} = 0.01818 0.0112 = 0.01818 x c e l l c o n s \tan t c e l l c o n s \tan t = 0.616 c o m^{- 1}$

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