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Q.

The specific conductivity of N/10 KCl solution at 20°C is 0.0212 ohm^-1 cm^-1 and the resistance of the cell containing this solution at 20°C is 55 $Ω$ . The cell constant is:

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a

3.324 cm^-1

b

2.372 cm^-1

c

1.166 cm^-1

d

3.682 cm^-1

answer is B.

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Detailed Solution

$\begin{array}{l} κ = Conductance \times \frac{l}{A} \\ \frac{l}{A} = κ \times \frac{1}{Conductance} = κ \times R = 0.0212 \times 55 = 1.166 {cm}^{- 1} \end{array}$

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