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The specific gravity of 98% H₂SO₄ is 1.8 g/cc. 50 ml of this solution is mixed with 1750 ml of pure water. Molarity of resulting solution is

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0.2 M

0.5 M

0.1 M

answer is B.

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Detailed Solution

$M_{1} = \frac{10 \times d}{M . wt} = 18; M_{1} V_{1} = M_{2} V_{2}$
$\Rightarrow$ 18 × 50 = M₂ × 1800 $\Rightarrow$ M₂ = 0.5 M

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