The specific heat of Argon at constant volume is 0.3122kJ/kg K. Find the specific heat of Argon at constant pressure if R = 8.314 kJ/kmole K. (Molecular weight of argon = 39.95) in J/kg K is .

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302.5

230.5

530.2

520.3

answer is A.

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Detailed Solution

$\begin{array}{l} C_{v} = 0 .3122 kj / kg - k; C_{p} = ? \\ R = 8 .314 kj / k mole; M = 39 .95 gm \\ C_{p} - C_{v} = R; M (C_{p} - C_{v}) = R \\ C_{p} - C_{v} = \frac{R}{M} \Rightarrow C_{p} = C_{v} + \frac{R}{M} \\ = 0 .3122 + \frac{8 .314 \times 10^{- 3}}{39 .95 \times 10^{- 3}} \\ = 0 .3122 + 0 .281 = 0 .5203 kj / kgk \\ = 520 .3 J / kgK \end{array}$

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