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Q.

The specific heats of iodine vapour and solid are 0.031 and 0.055 cal / g respectively. If heat of sublimation of iodine is 24 cal/ g at 200° C , what is its value at 250° C ?

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a

2.28 cal / g

b

22.8 cal / mol

c

0.228 cal / g

d

22.8 cal / g

answer is C.

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Detailed Solution

∆Cp=∆HT2-∆HT1T2-T1

∆CP=-0.055+0.031=-0.024

⇒-0.024=∆HT2-24250-200

⇒-0.024=∆HT2-2450

⇒-0.024×5=∆HT2-24

⇒∆HT2=22.8 cal/g.

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