Q.

The specific rotation of (+)-1-bromo-1-phenylethane changes from +15°to43° on reaction with NaOH under strict SN2  conditions. When a sample of (–)-1-bromo-1-phenylethane was treated with aqueous NaOH, the resulting solution has a specific rotation of  +10° . The % of the reactant that underwent SN2  reaction is

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answer is 23.24.

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Detailed Solution

Let x be the %  of inverted product.
x100×(43)(1x)10043=10x=61.63 
%  of retention product = 38.37
%  of SN1  = 76.74
% of  SN2 = 23.26

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