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Q.

The speed at the maximum height of a projectile is half of its initial speed of projection (u). The horizontal range of the projectile is

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a

3u22g

b

3u2g

c

u23g

d

2u23g

answer is A.

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Detailed Solution

minimum velocity ucosθ=u2 θ=60R=u2sin2θg=3u22g

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