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The speed of a car changes from 0 to $5 {ms}^{- 1}$ in the first phase and from $5 {ms}^{- 1}$ to $10 {ms}^{- 1}$ in the second phase and from $10 {ms}^{- 1}$ to $15 {ms}^{- 1}$ during the third phase. In which phase the increase in kinetic energy is more?

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first phase

second phase

third phase

same in all the three phases

answer is C.

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Detailed Solution

$∆ KE = \frac{1}{2} m (v^{2} - u^{2})$

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