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The speed of a car weighing $1500 kg$ increases $40 m / s$ to $50 m / s$ . The change in momentum is ____ $kg m / s$ .

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Detailed Solution

The speed of a car weighing

1500 kg

increases

40 m / s

50 m / s

. The change in momentum will be

15000 kg m / s .

Given that,
Mass of the car

(m) = 1500 kg

Initial velocity

u = 40 m / s

Final velocity

v = 50 m / s

From the relation of momentum, mass and velocity we have
Momentum = mass × velocity
Initial momentum

= 1500 \times 40

Final momentum

= 1500 \times 50

Change in momentum = initial momentum – final momentum

= > P = 1500 \times (40 - 50)

= > p = 15000 kg m / s

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