The speed of a particle executing SHM is given by the equation ${\mathrm{v}}^2=144-9{\mathrm{x}}^2$  then the wrong statements among the following is 

maximum velocity in SHM is at x = 0 that is when there is no displacement. 
Thus putting x = 0, the maximum velocity comes out to be = 12 units 
$\begin{array}{l}\mathrm{V}=\sqrt{144-9{\mathrm{x}}^2}\\ =3\sqrt{4^2-{\mathrm{x}}^2}\end{array}$ 
Comparing with the equation $\mathrm{V}=\mathrm{\omega }\sqrt{{\mathrm{A}}^2-{\mathrm{x}}^2}$  we get  $\mathrm{\omega }=3 \mathrm{and}\mathrm{A}=4$ 

maximum velocity =$A\omega =3\times 4=12$ units
As a result T = $2\mathrm{\pi }/3$  
Also we know acceleration =  $-{\mathrm{\omega }}^2\mathrm{x}$  in the case of SHM
For maximum acceleration $\mathrm{x}=\mathrm{A}=4$  which gives us maximum acceleration as 36 units, 
Hence option 2 is wrong.