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The speed of a swimmer is $4 {kmh}^{- 1}$ in still water. If the swimmer makes his strokes normal to the flow of river of width 1 km, he reaches a point 750 m down the stream on the opposite bank. The speed of the river water is _____ kmh^-1

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answer is 3.

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Detailed Solution

Given $\vec{V_{BG}} = 4 kmph$

$Time taken to cross the river is t = \frac{1 km}{4 {kmh}^{- 1}} = \frac{1}{4} hr$

$drift d = v_{river} \times t = \frac{3}{4} K m$

$∴ v = 3 km / hr$

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