The speed of an electron in the inner most orbit of the hydrogen (Bohr radius = 52.9 pm; ${\mathrm{m}}_{\mathrm{e}}=9.11\times {10}^{-31}\mathrm{kg}$) is

For the inner most orbit, the value of n is 1.

$$\begin{gathered} \mathrm{mvr}=\frac{\mathrm{nh}}{2\mathrm{\pi }} \\ 9.11\times {10}^{-31} \mathrm{kg}\times \mathrm{v}\times 52.9 \mathrm{pm}=\frac{1\times 6.626\times {10}^{-34}}{2\times 3.14} \\ \mathrm{v}=2.19\times {10}^{6 }\mathrm{m}/\mathrm{s} \end{gathered}$$