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Q.

The speed of electron in first Bohr orbit is c/137. The speed of electron in second Bohr orbit will be

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a

$\frac{c}{548}$

b

$\frac{c}{274}$

c

$\frac{2 c}{137}$

d

$\frac{4 c}{137}$

answer is C.

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Detailed Solution

(c)

$v_{n} = \frac{v_{1}}{n} ∴ v_{2} = \frac{c}{137 \times 2} = \frac{c}{274}$

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