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The spin-only magnetic moment value of an octahedral complex among ${CoCl}_{3} . 4 {NH}_{3}$ , ${NiCl}_{2} . 6 H_{2} O$ and ${PtCl}_{4} . 2 HCl$ , which upon reaction with excess of ${AgNO}_{3}$ gives $2$ moles of $AgCl$ is ____________ $B . M$ . (Nearest Integer)

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answer is 3.

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Detailed Solution

${CoCl}_{3} \cdot 4 {NH}_{3} \to [Co {({NH}_{3})}_{4} {Cl}_{2}] Cl {NiCl}_{2} \cdot 6 H_{2} O \to [Ni {(H_{2} O)}_{6}] {Cl}_{2} {PtCl}_{4} \cdot 2 HCl \to H_{2} [{PtCl}_{6}] [Ni {(H_{2} O)}_{6}] Cl$

nickel in +2 oxidation state will have two unpaired electron

$μ = \sqrt{2 (2 + 2)} B M = 2.84 BM \approx 3$ .

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