The spring balance A read 2 k.g. with a block m suspended from it. A balance B reads 5kg when a breaker with liquid is put on the pan of the balance. The two balances are now so arranged that the hanging mass is inside the liquid in the beaker as shown in fig. In this situation.

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$The balance A will read more than 2 kg .$

$The balance B will read more than 5 kg .$

$The balance A will read less than 2 kg . and B will read more than 5 kg .$

$The balance A and B will read 2 kg . and 5 kg respectively .$

answer is C, B.

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Detailed Solution

A buoyant force that is smaller than the weight of the body acts upward on the mass due to the displacement of water in the beaker generated by the mass. As a result, the weight that balance A reads is less than 2 kg.

Additionally, a downward acting reaction pair force of the buoyant force on mass acts on the water. As a result, this force (< 2 kg) increases the weight of the water, and balance B reads between 3kg and 5 kg.

Hence the correct answer is the balance A will read less than 2k kg and B will read between 5kg and 5kg.

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