The spring constant of spring $A$ is twice the spring constant of spring $B$. Each of the spring is cut into two pieces. First piece of spring $A$ is $\left(\raisebox{1ex}{$4$}\!\left/ \!\raisebox{-1ex}{$5$}\right.\right)$ of the total length. Second piece of spring $B$ is $\left(\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$6$}\right.\right)$ of its total length. Both springs are of equal length initially:

the ratio of force constant of second piece of spring $A$ to the first piece of spring $B$ is $\raisebox{1ex}{$5$}\!\left/ \!\raisebox{-1ex}{$3$}\right.$

the ratio of force constant of first piece of spring $B$ to the first piece of spring $A$ is $2$

the ratio of force constant of second piece of spring $A$ to the first piece of spring $B$ is $\raisebox{1ex}{$7$}\!\left/ \!\raisebox{-1ex}{$5$}\right.$

the ratio of force constant of first piece of spring $B$ to the first piece of spring $A$ is $\left(\raisebox{1ex}{$12$}\!\left/ \!\raisebox{-1ex}{$5$}\right.\right)$