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The springs shown are identical. When A=4kg , the elongation of spring is 1 cm. If B=6kg, the elongation produced by it is

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4 cm

3 cm

2 cm

1 cm

answer is B.

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Detailed Solution

$F = kx \Rightarrow mg = kx \Rightarrow m \propto kx$

Hence $\frac{m_{1}}{m_{2}} = \frac{k_{1}}{k_{2}} \times \frac{x_{1}}{x_{2}} \Rightarrow \frac{4}{6} = \frac{k}{k / 2} \times \frac{1}{x_{2}}$

$\Rightarrow x_{2} = 3 cm$ .

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