The stability of given free radicals in decreasing order is
1) ${CH}_{3} - \overset{∙}{C} H_{2}$
2) ${CH}_{3} - \overset{∙}{C} H - {CH}_{3}$
3)
4) $\overset{∙}{C} H_{3}$

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$3 > 4 > 1 > 2$

$1 > 2 > 3 > 4$

$3 > 2 > 4 > 1$

$3 > 2 > 1 > 4$

answer is D.

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Detailed Solution

For a given free radicals, if the alkyl groups attached are increases then positive inductive effect (+I.E) is increased and then stability also increased. Among given all free radicals, tertiary butyl radical is most stable. The decreasing order of stability of free radicals is $3 > 2 > 1 > 4$

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