The standard cell potential for the electrochemical cell $Ag / {Ag}^{+} | | AgI / Ag; E_{I^{-} / AgI (s) / Ag}^{0} = - 0 .151 V, E_{{Ag}^{+} / Ag}^{0} = 0 .799 V$

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- 0.648 V

+ 0.950 V

+ 0.648 V

- 0.950 V

answer is B.

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Detailed Solution

$\begin{array}{l} Ag | {Ag}^{+} | | AgI | Ag \\ E_{cell} = E_{Ag / {Ag}^{+}}^{0} + E_{AgI (s) / Ag}^{0} \\ = - 0 .799 - 0 .151 = - 0 .950 V \end{array}$

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