The standard electrode potential of a daniell cells is 1.1V. Find the standard Gibbs energy for the reaction Zn(s)+Cu (aq)2+→Zn (aq)2++Cu(s)

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The standard electrode potential of a daniell cells is 1.1V. Find the standard Gibbs energy for the reaction

$Z n_{(s)} + C u_{^{(a q)}}^{2 +} \to Z n_{^{(a q)}}^{2 +} + C u_{(s)}$

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$- 2123 K J / m o l$

$- 21.23 K J / m o l$

$- 212.3 K J / m o l$

$- 2.123 K J / m o l$

answer is A.

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Detailed Solution

$Z n_{(s)} + C u_{(a q)}^{2 +} \to Z n_{(a q)}^{2 +} + C u_{(s)}$

$Δ G ° = - n F E_{c e l l}^{°} = - 2 \times 96487 \times 1.1 = - 212271.4 J o u l e s m o l^{- 1} = - 212.27 K J m o l^{- 1}$

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