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Q.

The standard electrode potential of a daniell cells is 1.1V. Find the standard Gibbs energy for the reaction 

Zn(s)+Cu (aq)2+→Zn (aq)2++Cu(s)

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a

−2123KJ/mol

b

−21.23KJ/mol

c

−212.3KJ/mol

d

−2.123KJ/mol

answer is A.

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Detailed Solution

Zn(s)+Cu(aq)2+→Zn(aq)2++Cu(s)

ΔG°=−nFEcell°=−2×96487×1.1=−212271.4 Joules mol−1=−212.27 KJ mol−1

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