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The standard electrode reduction potentials of $Z n a n d A g a n d C u$ are $- 0.76, 0.80 a n d 0.34$ volt respectively then

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Cu can oxidise Zn and Ag

Zn can reduce $A g^{+} a n d C u^{2 +}$

Ag can oxidize Zn and Cu

Ag can reduce $Z n^{2 +} a n d C u^{2 +}$

answer is A.

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Detailed Solution

Given $E_{Z n^{2 +} / Z n} = - 0.76 o r E_{Z n / Z n^{2 +}} = 0.76$

$\begin{array}{l} E_{A g^{+} / A g} = 0.80 o r E_{A g / A g^{+}} = - 0.80 \\ E_{C u^{2 +} / C u} = 0.34 o r E_{C u / C u^{2 +}} = - 0.34 \end{array}$

As oxidation potential order is $A g < C u < Z n$

More the oxidation potential more the tendency to oxidise itself
As Ag has less oxidation potential among all, hence Ag canoxidise Zn and Cu

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