The standard electromotive force of a galvanic cell involving cell reaction with n = 2 is found to be 0.295 V at 250C. The equilibrium constant of the reaction would be

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1.0 × 10²

4.0 × 10¹²

1.0 × 10¹⁰

2.0 × 10¹¹

answer is A.

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Detailed Solution

Using Nernst equation:

$E_{cell}^{o} = \frac{2.303 RT}{nF} logK$
${E_{cell}}^{0} = \frac{2.303 \times 8.314 \times 298}{2 \times 96500} \log_{10} K \log_{10} K = \frac{0.295 \times 2}{0.0591} = 10 antilog (\log_{10} K) = antilog 10 K = 1 \times 10^{10}$

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