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Q.

The standard enthalpies of formation of CO2(g),H2O(l) and glucose (s) at 25°C are −400 kJ/mol,−300 kJ/mol and−1300 kJ/mol , respectively, the standard enthalpy of combustion per gram of glucose at 25°C is

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a

2900 KJ

b

-16.11 KJ

c

-2900 KJ

d

16.11 KJ

answer is C.

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Detailed Solution

Combustion of glucose

C6H12O6⟶O26CO2+6H2OΔHcombustion =6×ΔfHCO2+6×ΔfHH2O-ΔfHC6H12O6=(6×(-400)+6×(-300)-(-1300))=-2900 kJ=-2900KJ/mol=-2900KJ180 g=-16.11KJ/g

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