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Q.

The standard enthalpy of the decomposition of $N_{2} O_{4} to N O_{2}$ is 58.0kJ and standard entropy of this reaction is 176.7 J/K. Therefore the standard free energy changes for this reaction at _______________(in KJ) (rounding off to nearest integer)

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answer is 5.

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Detailed Solution

Give that standard enthalpy of decompositions $(Δ H) = 58.04 k J$
Standard entropy $(Δ S) = 176.7 k J / K = 176.7 \times 10^{- 3} k J / K$
And temperature $(T) = 25 ° C + 273 = 298 K$
Change in free energy
$(Δ G) = Δ H - T Δ S = 58.04 - 298 \times (176.7 \times 10^{- 3}) = 5.39 k J$

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