The standard equilibrium constant of the reaction
$2 {Cu}^{+} (aq) ⇌ {Cu}^{2 +} (aq) + Cu (s)$
is about [Given: $E^{\circ} ({Cu}^{+} ∣ Cu) = 0.53 V and E^{\circ} ({Cu}^{2 +} ∣ Cu) = 0.34 V]$

Question

The standard equilibrium constant of the $$reaction2Cu+(aq)$$⇌$$Cu2+(aq)+Cu(s)is$$ about [Given: E∘$$Cu+$$∣$$Cu=0.53V$$ and E∘$$Cu2+$$∣$$Cu=0.34V$$

Infinity Learn · Accepted Answer

Consider the $$cellCu(s)Cu2+(1M)Cu+(1M)CuThe$$ cell reaction is RHC     $$Cu++e$$−→CuLHC    Cu→$$Cu2++2e$$−Cell reaction     $$2Cu+$$→$$Cu+Cu2+$$ Cell potential     Ecell∘$$=E$$∘$$Cu+$$∣Cu−−$$ECu2+$$∣Cu∘Thus  Ecell∘$$=ECu+$$∣Cu∘−$$ECu2$$∣Cu∘$$=0.53V$$−$$0.34V=0.19V$$ Finally −nFEcell∘$$=$$−RTln⁡Keq∘  or  log⁡Keq∘$$=nEcell$$∘$$2.303(RT/F)or$$ log⁡Keq∘$$=(2)(0.19V)(0.059V)=6.44Keq$$ ∘$$=106.44=2.76$$×$$106$$

The standard equilibrium constant of the reaction
$2 {Cu}^{+} (aq) ⇌ {Cu}^{2 +} (aq) + Cu (s)$
is about [Given: $E^{\circ} ({Cu}^{+} ∣ Cu) = 0.53 V and E^{\circ} ({Cu}^{2 +} ∣ Cu) = 0.34 V]$

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The standard equilibrium constant of the reaction2Cu+(aq)⇌Cu2+(aq)+Cu(s)is about [Given: E∘Cu+∣Cu=0.53V and E∘Cu2+∣Cu=0.34V

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The standard equilibrium constant of the reaction
$2 {Cu}^{+} (aq) ⇌ {Cu}^{2 +} (aq) + Cu (s)$
is about [Given: $E^{\circ} ({Cu}^{+} ∣ Cu) = 0.53 V and E^{\circ} ({Cu}^{2 +} ∣ Cu) = 0.34 V]$