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Q.

 The standard free energy change of a reaction is ΔG°=-115 kJ at 298 K. Calculate the value of log10KpR=8.314JK-1 mol-1

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a

 20.16

b

13.83

c

2.016

d

2.303

answer is A.

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Detailed Solution

ΔG°=-RTlnkeq ΔG°=ΔH°-TΔS°=-RTlnkeq

log Kp = 115×10002.303×8.314×298=20.1547≅20.16

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 The standard free energy change of a reaction is ΔG°=-115 kJ at 298 K. Calculate the value of log10KpR=8.314JK-1 mol-1